Question

The van der Waal's radii $O,N,Cl,F$ and $Ne$ increase in the order:

• A. $F,O,N,Ne,Cl$
• B. $Ne,F,O,N,Cl$
• C. $F,Cl,O,N,Ne$
• D. $N,O,F,Ne,Cl$

Answer 1

The correct option is C $F,Cl,O,N,Ne$

$Radious\propto \frac{1}{Z_{eff}}$

• As the $Z_{eff}$ increase in a period for left to right direction so the radius decreases.
  
• But in the case of Nobel gases, the van der Waal's radius is much larger than other elements. This is because of the more electron-electron repulsion.
  
• In a group radious increase down the group.

So the order is-

$F<Cl<O<N<Ne$