The van der Waals' equation for (12) mole of a gas is:
A
(P+aV2)(V−b)=RT
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B
(P+a4V2)(V−b2)=RT2
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C
(P+a4V2)(V−b2)=RT
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D
(P+a4V2)(V−b2)=2RT
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Solution
The correct option is B(P+a4V2)(V−b2)=RT2 Vander Waal's eqn is: (P+an2V2)(V−nb)=nRT For n=1 (P+aV2)(V−b)=RT When n=12 (P+a4V2)(V−b2)=RT2 (P+a4V2)(2V−b)=RT