The Van't Hoff factor for 0.1 M La $(N O_{3})_{3}$ solution is found to be 2.74 the percentage dissociation of the salt is :

85%

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58%

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65.8%

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52%

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Solution

The correct option is C 58%
Let x be the percentage dissociation.

$L a (N O_{3})_{3} \to L a^{3 +} + 3 {N O}_{3}^{-}$
Initial moles 1 0 0
Moles after dissociation 1-x x 3x

The Van't Hoff factor is 2.74

$i = \frac{A c t u a l n u m b e r o f m o l e s}{e x p e c t e d n u m b e r o f m o l e s}$

$2.74 = \frac{1 + 3 α}{1}$

$α = 0.58$

$α % = 58 %$

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