The van't hoff factor for a very dilute solution of ${F e}_{2} {({S O}_{4})}_{3}$ is:

9

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5

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24

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16

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Solution

The correct option is B $5$
$F e_{2} (S O_{4})_{3}$ dissociates into $2 F e^{3 +} + 3 S O_{4}^{2 -}$
Now
$i = 1 + α (n - 1)$
$i = 1 + 1 \times (5 - 1)$
So, $i = 5$

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