Question

The van't Hoff factor for $H{F}_{aq.}$ is 2

• A. True
• B. False

Answer 1

The correct option is B False

The van't Hoff factor is given by the expression
$i=\frac{\text{number of solute particles present in solution (n observed)}}{\text{theoretical number of solute particles due to solution of non electrolyte (n theoretical)}}$
HF is a weak acid. It undergoes incomplete dissociation.
$HF\rightleftharpoons H^{+}+F^{-}$
Hence, the van't Hoff factor for HF is less than 2.