Question

The van't Hoff factor (i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is :

• A. 2
• B. 3
• C. 0
• D. 1

Answer 1

The correct option is B 3

$Ba(OH{)}_2$ is a strong electrolyte, so its 100% dissociation occurs in solution.

Van't off factor(i) = Total number of ions present in the solution

$Ba(OH{)}_2\to B{a}^{+2}+2O{H}^{-}$

So, the total number of ions in the solution is 3.

Hence, option B is correct.