Question

The van 't Hoff factor of a weak electrolyte $AB$ in a solution is $1.1$. Its degree of dissociation would be 0.1. If true enter 1 else 0.

Answer 1

we have,

$\alpha =\frac{i-1}{n-1}$

$AB\to A^{+}+B^{-}$, n= 2

$\alpha =\frac{1.1-1}{2-1}$

$\alpha =0.1$