The van't Hoff factor of $B a C l_{2}$ at 0.01 M concentration is 1.98. The percentage of dissociation of $B a C l_{2}$ at this concentration is:

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100

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Solution

The correct option is A 49

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0.01 M

B a {C l}_{2}

1.98

B a {C l}_{2}

The Van’t Hoff factor for 0.1M $B a C l_{2}$ is 2.74. The percentage dissociation of the salt is

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0.01 M

0.1 M

2.74

B a C l_{2} (a q)

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