Question

The van't Hoff's factor for 0.1 M $Ba(N{O}_3{)}_2$ solution is $2.74$. The degree of dissociation is:

• A. $91.3$%
• B. $87$%
• C. $100$%
• D. $74$%

Answer 1

The correct option is B $87$%

$i=1+2\alpha$ ----------- [for $Ba(N{O}_3{)}_2\rightleftharpoons B{a}^{2+}+2N{O}_3^{-}$]

$\therefore 2.74=1+2\alpha$
$\therefore \alpha =\frac{1.74}{2}=0.87=$ 87%

The van't Hoff's factor for 0.1 M $Ba(N{O}_3{)}_2$ solution is 2.74. The degree of dissociation is 87 %.

Hence, the correct option is $B$