Question

The Van't Hoff's factor ${}^{\prime }{i}^{\prime }$ accounts for:

• A. extent of dissolution of solute
• B. extent of mobility of solute
• C. extent of solubility of solute
• D. extent of dissociation of solute

Answer 1

The correct option is D extent of dissociation of solute

The Van't Hoff's factor 'i' accounts for the extent of dissociation of solute.

For example, one molecule of $NaCl$ completely dissociates to produce two ions.

$NaCl\to N{a}^{+}+C{l}^{-}$

Hence, its Van't Hoff's factor 'i' is 2.

One molecule of $N{a}_{2}S{O}_4$ completely dissociates to produce three ions.

$N{a}_{2}S{O}_4\to 2N{a}^{+}+S{O}_4^{2-}$

Hence, its Van't Hoff's factor 'i' is 3.