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Byju's Answer
Standard XII
Chemistry
Liquefaction of Gases and Critical Constants
The vander wa...
Question
The vander waals constants for
H
C
l
are a
371.843
K
P
a
and
b
=
40.8
c
m
3
m
o
l
−
1
. Choose the correct options:
A
The critical pressure is
8.273
M
P
a
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B
The critical temperature is
224.8
K
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C
The critical volume is
122.4
c
m
3
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D
The critical temperature is
324.8
K
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Solution
The correct option is
A
The critical pressure is
8.273
M
P
a
Critical pressure
P
c
=
a
27
b
2
given
a
=
371.843
K
P
a
=
371.843
×
10
−
3
Pa
b
=
40.8
c
m
3
m
o
l
−
1
P
c
=
371.843
×
10
3
27
×
(
40.8
)
2
×
10
−
6
=
8.273
×
10
6
P
a
=
8.273
MPa
Suggest Corrections
0
Similar questions
Q.
For a gas, the critical temperature and critical pressure are
27
0
C and
500
atm respectively. The vander Waals constant b
(
m
o
l
−
1
l
)
for the gas is?
Q.
The van der waals constant for
H
C
l
are
a
=
371.843
kPa.dm
6
mol
–
2
and
b
=
40.8
cm
3
mol
−
1
. Find the critical pressure of this substance.
Q.
The essential conditions for liquefaction of gases were discovered by Andrews in
1869
as a result of his study of pressure-volume-temperature relationship for
C
O
2
. It was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature
(
T
c
)
. The pressure required to liquefy a gas at this temperature is called the critical pressure
(
P
c
)
. The volume occupied by one mole of the substance at the critical temperature and pressure is called critical volume. Critical constants are related with van der Waals' constant as follows:
V
c
=
3
b
,
P
c
=
a
27
b
2
,
T
c
=
8
a
27
R
b
.
Which of the following parameters is three times the van der Waals' constant
′
b
′
?
Q.
The essential conditions for liquefaction of gases were discovered by Andrews in
1869
as a result of his study of pressure-volume-temperature relationship for
C
O
2
. It was found that above a certain temperature, it was impossible to liquefy a gas whatever the pressure was applied. The temperature below which the gas can be liquefied by the application of pressure alone is called critical temperature
(
T
c
)
. The pressure required to liquefy a gas at this temperature is called the critical pressure
(
P
c
)
. The volume occupied by one mole of the substance at the critical temperature and pressure is called critical volume. Critical constants are related with van der Waals' constant as follows:
V
c
=
3
b
,
P
c
=
a
27
b
2
,
T
c
=
8
a
27
R
b
.
The relationship between
P
C
,
V
C
and
T
C
is
Q.
The van der Waals constants for
H
C
l
are
a
=
371.843
kPadm
6
mol
–
2
and
b
=
40.8
cm
3
mol
−
1
.What is the critical pressure of
H
C
l
?
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