Question

The vapor density of completely dissociated $N{H}_{4}Cl$ would be

• A. same as that of $N{H}_{4}Cl$
• B. double than that of $N{H}_{4}Cl$
• C. half than that of $N{H}_{4}Cl$
• D. slightly less than that of $N{H}_{4}Cl$

Answer 1

The correct option is A same as that of $N{H}_{4}Cl$

On dissolution of $N{H}_{4}Cl$ into $N{H}_3+HCl$ number of moles become double. Hence, volume is doubled and therefore, density is halved.