Question

The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at ATP will be

• A. 11.2 L
• B. 22.4 L
• C. 1 L
• D. 44.8 L

Answer 1

The correct option is A 11.2 L

Molecular weight= $2\times V.D=2\times 11.2=22.4$
$\because$ 22.4gm of gas occupies 22.4L at S.T.P.
$\therefore$ 11.2gm of gas occupies $\frac{22.4}{22.4}\times 11.2=11.2L$.