The vapour density of a gas is 11.2. The volume occupied by 11.2 g of the gas at ATP will be
A
11.2 L
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B
22.4 L
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C
1 L
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D
44.8 L
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Solution
The correct option is A 11.2 L Molecular weight= 2×V.D=2×11.2=22.4 ∵ 22.4gm of gas occupies 22.4L at S.T.P. ∴ 11.2gm of gas occupies 22.422.4×11.2=11.2L.