Question

The vapour density of a gas is 11.2. The volume occupied by 11.2 $gm$ of the gas at $STP$ is:

• A. 11.2 $lit$
• B. 4 $lit$
• C. 2 $lit$
• D. 22.4 $lit$

Answer 1

The correct option is A 11.2 $lit$

$Vapourdensity=0.5\times molarmass$

$\Rightarrow Molarmass=22.4gm$

So, 11.2 $gm$ of the gas = 0.5 moles.

At STP, 1 mole of the gas occupies 22.4 L of volume.

Volume occupies at $STP$ is 0.5 times 22.4 = 11.2 litres

Option A is correct.