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Question

The vapour density of gas A is four times that of B. If the molecular mass of B is M, then the molecular mass of A will be:

A
M
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B
4M
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C
M4
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D
2M
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Solution

The correct option is B 4M
According to the relationship:
Molar mass=2×vapour density
We have given mass of B is M, thus vapour density of B is,
V.D.=M (Numerical value)2
Also, given that vapour density of A is four time that of B, then
Therefore, V.D. of A = 4×V.D.
MA2=4×MB2
MA=4MB=4M

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