Question

The vapour density of Hydrogen peroxide is equal to molecular weight of NH₃.

• A. True
• B. False

Answer 1

The correct option is A True

• Vapour density is the weight of volume of pure vapour or gas compared to an equal volume of dry air at the same temperature and pressure.
• We know that Molecular weight = 2× vapour density.

Therefore vapour density of Hydrogen peroxide (H₂O₂) = $\frac{\mathrm{Molecular}\mathrm{weight}\mathrm{of}{\mathrm{H}}_2{\mathrm{O}}_2}{2}$

Here the molecular weight of Hydrogen peroxide (H₂O₂) = (2×1) + (2×16) = 34g

Therefore vapour density of Hydrogen peroxide (H₂O₂) =$\frac{34}{2}$=17

The vapour density of Hydrogen peroxide (H₂O₂) =17

• Molecular weight of Ammonia (NH₃) = 14+ 1×3 = 14+3=17 g

Hence, the vapour density of Hydrogen peroxide (H₂O₂) is equal to the molecular weight of Ammonia (NH₃)

So, the vapour density of Hydrogen peroxide is equal to molecular weight of NH₃. The statement is true.