Question

The vapour density of $N_2{O}_4$ at a certain temperature was 30. What is the percentage of dissociation of $N_2{O}_4$ at this temperature?

• A. 53.33%
• B. 58.33%
• C. 68.5%
• D. 62.5%

Answer 1

The correct option is A 53.33%

For a reaction of type
$A\rightleftharpoons yB$
$\alpha =\frac{D-d}{d(y-1)}$
D= initial vapour density
d= final vapour density
Here we can say,
D= $\frac{92}{2}=46$
$\alpha =\frac{46-30}{30(2-1)}=0.5333$
So, % dissociation = 53.33%