The vapour of a carboxylic acid HA when passed over MnO2 at 573 K yields propanone. What is the acid HA?
a) Methanoic acid
b) Ethanoic acid
c) Propanoic acid
d) Butanoic acid

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Solution

Answer: b
Explanation: The vapour of ethanoic acid (HA) when passed over $M n O_{2}$ at $573$ $K$ yields propanone.

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