MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relative Lowering of Vapour Pressure

The vapour pr...

Question

The vapour pressure of a pure liquid at $25$ is 100 mm $H g$ . Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.

Open in App

Solution

$P^{0} = 100 m m$ $H g$
Relative lowering of vapor pressure $(P - P^{0}) = x \times P^{0} = 0.8 \times 100 m m H g = 80 m m H g$
Therefore, the relative lowering of vapor pressure is $80$ mm of $H g .$

Suggest Corrections

thumbs-up

1

Similar questions

p_{A}^{o}

is the vapour of pure solvent and

p_{A}

is the vapour pressure of solution. If

X_{B}

is the mole fraction of solute and

X_{A}

is the mole fraction of the solvent. What is the expression for relative lowering of vapour pressure of the solution?

Q. If vapour pressure of pure liquid

A

100 mm Hg

and Vapour pressure of pure liquid

B

150 mm Hg

2

A

3

B

are mixed to form an ideal solution. The vapour pressure of solution will be:

Q. Vapour pressure of liquids

A

B

298 K

300 m m H g

450 m m H g

. Calculate the mole fraction of

A

in the mixture.

[Given total vapour pressure of solution

= 405 m m H g

Q. The vapour pressure of a pure liquid A is 40 mm of Hg at 310 K. The vapour pressure of this liquid in a solution with liquid B is 32 mm of Hg. The mole fraction of A in the solution, if it obey's Raoult's law, is?

Q. In a binary mixture of two ideal volatile liquids A and B, calculate the mole fraction of component A in vapour phase if:
Vapour pressure of A in pure state is

500 m m H g

Vapour pressure of B in pure state is

700 m m H g

(P_{T})

of the solution is

600 m m H g

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Relative Lowering of Vapour Pressure

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Relative Lowering of Vapour Pressure

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon