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Relative Lowering of Vapour Pressure

The vapour pr...

Question

The vapour pressure of a pure liquid at $25$ is 100 mm $H g$ . Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.

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Solution

$P^{0} = 100 m m$ $H g$
Relative lowering of vapor pressure $(P - P^{0}) = x \times P^{0} = 0.8 \times 100 m m H g = 80 m m H g$
Therefore, the relative lowering of vapor pressure is $80$ mm of $H g .$

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