The vapour pressure of a solution having 0.9 mole fraction of water in ethanol water is :
A
39.3
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B
11.20
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C
34
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D
33.92
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Solution
The correct option is D33.92 The vapour pressure of a solution having 0.9 mole fraction of water in ethanol water is 33.92 mm Hg. Mole fraction of ethanol = 1 - 0.9 = 0.1 mol PM=P0H2O⋅XH2O+P0ethanol⋅Xethanol =32.8×0.9+44×0.1 =33.92mmHg