The vapour pressure of a solution of the liquids A (P0=80mmofHgandXA=0.4) and B (P0=120mmofHgandXB=0.6) is observed to be 100 mm of Hg. It shows that the solution exhibits:
A
Positive deviation from ideal behaviour
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B
Negative deviation from ideal behaviour
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C
Ideal behaviour
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D
Positive deviation at low concentrations and negative at higher concentrations
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Solution
The correct option is B Negative deviation from ideal behaviour From Raoults law, Ptotal=p0A×XA+p0B×XB =80.0×0.4+120.0×0.6 =104mmofHg The observed Ptotal is 100 mm of Hg which is less than 104 mm of Hg. Hence the solution shows negative deviation.