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Raoult's Law

The vapour pr...

Question

The vapour pressure of a solution with volatile components A and B is given by the equation P. solution = 4.0 + 20 X If mole fraction of B in vapour phase is 0.6, the mole fraction of A in solution phase is

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Similar questions

Q. For an ideal binary liquid solution with

P_{A}^{0} > P_{B}^{0}

which relation between

X_{A}

(mole fraction of A in liquid phase) and

Y_{A}

(mole fraction of A in vapour phase) is correct,

X_{B}

Y_{B}

are mole fraction of B in liquid and vapour phase respectively:

Q. Consider a binary mixture of two ideal volatile liquids A and B.
Which of the following represents the correct relation?

(Here total pressure of the solution is

(P_{T})

, mole fraction of component A in vapour phase is

y_{A}

, vapour pressure of component A and B in pure states is

p_{A}^{\circ} a n d p_{B}^{\circ}

Q. In a binary mixture of two ideal volatile liquids A and B, calculate the mole fraction of component A in vapour phase if:
Vapour pressure of A in pure state is

500 m m H g

Vapour pressure of B in pure state is

700 m m H g

(P_{T})

of the solution is

600 m m H g

Q. An ideal solution has two components

A

B

A

is more volatile than

B

P_{A}^{\circ} > P_{B}^{\circ}

P_{A}^{\circ} > P_{t o t a l}

X_{A}

Y_{A}

are mole fractions of components

A

in liquid and vapour phases, then :

Q. The vapour pressure of a solvent

A

0.80

atm. When a non-volatile substance

B

is added to this solvent, its vapour pressure drops to

0.6

atm. The mole fraction of

B

in the solution is:

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