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Standard XII

Chemistry

Molality

The vapour pr...

Question

The vapour pressure of pure benzene at $88^{o} C$ is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene-toluene mixture boiling at $88^{o} C$ .

x_{b e n z e n e} = 0.66; x_{t o l u e n e} = 0.34

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x_{b e n z e n e} = 0.34; x_{t o l u e n e} = 0.66

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x_{b e n z e n e} = x_{t o l u e n e} = 0.5

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x_{b e n z e n e} = 0.75; x_{t o l u e n e} = 0.25

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Solution

The correct option is A $x_{b e n z e n e} = 0.66; x_{t o l u e n e} = 0.34$

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The vapour pressure of pure benzene at 88oC is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene-toluene mixture boiling at 88oC.

The correct option is A xbenzene=0.66;xtoluene=0.34

The vapour pressure of pure benzene at $88^{o} C$ is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene-toluene mixture boiling at $88^{o} C$ .

The correct option is A $x_{b e n z e n e} = 0.66; x_{t o l u e n e} = 0.34$