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Question

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolyte solid weighing 0.5 g when added to 39 g of benzene (molar mass 78 g mol1), vapour pressure becomes 0.845 bar. What is the molar mass of the solid substance?

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Solution

p0pp0=W2M1W1M2
p0=0.850bar= vapour pressure of pure benzene.
p=0.845bar= vapour pressure of solution.
W1=39g= mass of benzene
W2=78g= mass of solute
M1=78g/mol= Molar mass of benzene.
M2= Molar mass of solute.
0.850bar0.845bar0.850bar=0.5g×78g/mol39g×M2
M2=170g/mol

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