The vapour pressure of pure water is $23.8 m m H g$ at $25^{0} C$ . What is the vapour pressure of $2.50 m o l a l C_{6} H_{12} O_{6}$ ?

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Solution

vapour pressure of water $P_{A}^{O} = 23.8 m m H g$
molarity of solution $= 2.5 m o l a l$
Let amount of water $= 1 k g$
number of mole of $C_{6} H_{12} O_{6} = 2.5$
number of mole of water $= \frac{1000}{18}$
mole fraction of water $X_{A} = \frac{\frac{1000}{18}}{\frac{1000}{18} + 2.5} = \frac{1000}{1045}$
Vapour pressure $P_{A} = P_{A}^{O} X_{A}$
$= 23.8 \times \frac{1000}{1045} = 22.775 m m H g$

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