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Byju's Answer
Standard XII
Chemistry
Relative Lowering of Vapour Pressure
The vapour pr...
Question
The vapour pressure of pure water is
32.8
m
m
of
H
g
. It is mixed with ethanol which has mole fraction
0.9
.
Find the vapour pressure of the resulting solution:
A
39.3
m
m
H
g
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B
36.0
m
m
H
g
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C
29.5
m
m
H
g
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D
28.8
m
m
H
g
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Solution
The correct option is
C
29.5
m
m
H
g
The reduction of the vapour pressure of the solvent is given as follows:
p
1
=
x
.
p
1
0
Here,
p
1
is the vapour pressure of the solution.
p
1
0
is the vapor pressure of pure solvent.
x
is the mole fraction of solute.
Vapor pressure of pure water is
p
1
0
=
32.8
mm of Hg
Mole fraction of ethanol
=
x
=
0.9
Vapor pressure of solution is
0.9
×
32.8
=
29.52
mm of Hg
Suggest Corrections
0
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