The vapour pressure of the solution of two liquids A p-80 mm and p -120 mm is found to be 100 mm when - A -0-4- The result shows that-A- Solution exhibits ideal behaviourB- - H solution -0C- Solution shows negative deviationD- Solution will show positive deviations for lower concentration and negative deviation for higher concentrations

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Standard XII

Chemistry

Ideal Solutions

The vapour pr...

Question

The vapour pressure of the solution of two liquids A $(p^{\circ} = 80 m m)$ and $(p^{\circ} = 120 m m)$ is found to be $100 m m$ when $χ_{A} = 0.4$ . The result shows that:

Solution exhibits ideal behaviour

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Δ H_{s o l u t i o n} > 0

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Solution shows negative deviation

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Solution will show positive deviations for lower concentration and negative deviation for higher concentrations

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Solution

The correct option is C Solution shows negative deviation
Given,
$χ_{A} = 0.4$
$∴ χ_{B} = 1 - 0.4 = 0.6$
Hence, $P_{t o t a l} = 0.4 \times 80 + 0.6 \times 120 = 104 > 100 m m o f H g P_{o b s} < P_{c a l}$
So, solution will show negative deviation from ideal behaviour.

Hence $Δ H_{s o l u t i o n}$ is also less than $0$ , since intermolecular forces will be high.

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Q. CASE1: Read the passage given below and answer the following question.

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The vapour pressure of the solution of two liquids A (p∘=80 mm) and (p∘=120 mm) is found to be 100 mm when χA=0.4. The result shows that:

The correct option is C Solution shows negative deviationGiven, χA=0.4 ∴χB=1−0.4=0.6 Hence, Ptotal=0.4×80+0.6×120=104>100 mm of HgPobs<Pcal So, solution will show negative deviation from ideal behaviour. Hence ΔHsolution is also less than 0, since intermolecular forces will be high.

The vapour pressure of the solution of two liquids A $(p^{\circ} = 80 m m)$ and $(p^{\circ} = 120 m m)$ is found to be $100 m m$ when $χ_{A} = 0.4$ . The result shows that: