Question

The vapour pressure of water at ${25}^{o}C$ is 0.0313 atm. Calculate the values of $K_p$ and $K_c$ at ${25}^{o}C$ for the equilibrium $H_{2}O\left(l\right)\rightleftharpoons H_{2}O\left(g\right)$

• A. $K_p=0.0313atm,K_c=1.28\times {10}^3$
• B. $K_p=0.0626atm,K_c=1.28\times {10}^3$
• C. $K_p=0.0626atm,K_c=2.56\times {10}^3$
• D. None of these

Answer 1

The correct option is A $K_p=0.0313atm,K_c=1.28\times {10}^3$

$H_{2}O\left(l\right)\rightleftharpoons H_{2}O\left(g\right)$

$K_P=P_{H_{2}O}=0.313$ atm

$K_C=\frac{0.313}{(0.0821\times 298{)}^1}=1.28\times {10}^3$