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Question

The vapour pressure of water at 80oC is 355 torr. A 100ml vessel contained water-saturated oxygen at 80oC , the total gas pressure being 760 torr. The contents of the vessel were pumped into a 50ml vessel at the same temperature. What were the partial pressures of oxygen and water vapor? What was the total pressure in the final equilibrium state? Neglect the volume of any water which might condense.

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Solution

vapor pressure of water remain constant, it depend only on temperature and independent to the volume of container,it remain constant in 100 ml and 50 ml container if temperature is constant

total pressure =partial pressure of of oxygen +vapor pressure of water

vapor pressure of water=355 torr

total pressure=760 torr

partial pressure of of oxygen=760–355=405 torr

when volume of container is half, pressure of O2 become double and vapor pressure is remain constant

P1V1=P2V2

405 X 100=50 X P2

P2 = 810 torr =partial pressure of of oxygen

vapor pressure of water=355torr

total pressure in 50 ml container =partial pressure of of oxygen +vapor pressure of water

=810+355

=1165torr


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