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Question

The vapour pressure of water at room temperature is 23.8 mm Hg. The vapour pressure of an aqueous solution of sucrose with mole fraction 0.1 is equal to :


A
23.9 mm Hg
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B
24.2 mm Hg
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C
21.42 mm Hg
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D
31.44 mm Hg
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Solution

The correct option is C $$21.42$$ mm Hg
$$P_o$$ (Vapour pressure of water) = 23.8 $$mm Hg$$
$$P_s$$ (Vapour pressure of sucrose) = ?
on solving as attached in the image we get 
$$P_s$$ (Vapour pressure of sucrose) = 21.42 $$mm Hg$$
$$\dfrac{P_o-P_s}{P_o}=0.1$$ (mole fraction)
$$\dfrac{23.8-P_s}{23.8}=0.1$$
$$23.8-P_s=2.38$$ or $$P_s=21.42$$ mm of Hg

Chemistry

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