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Question

The vapours of organic compound was burnt in oxygen. Equal volume of both gaseous substance were taken at same pressure and temperature. After the reaction, the system was returned to the original condition and it turn out that its volume has not changed. The product of combustion contain 50% CO2(g) and 50% H2O(g) by volume and no other gas. Find the molecular weight of organic compound (in gram/mol) in question.

A
30
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B
35
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C
40
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D
46
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Solution

The correct option is A 30
Let the organic compound be X.

The volume of a gas is directly proportional to the number of moles.

According to the given data, 1 mole of X combines with 1 mole of oxygen to form 1 mole of carbon dioxide and 1 mole of water.

X+O2CO2+H2O

Thus the molecular formula of X is CH2O.

Its molecular weight is 12+2+16=30 g/mol

Hence, the correct option is A

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