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Steps for Balancing Chemical Equations

The variable ...

Question

The variable coefficients a, b, c and d are considered for balancing the chemical equation.

The relation we get by balancing K in the following equation is:

A

a=c

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B

a=3c

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C

a=2c

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D

2a=c

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Solution

The correct option is C
a=2c

$\begin{matrix} N u m b e r o f K a t o m s o n p r o d u c t s i d e & N u m b e r o f K a t o m s o n r e a c t a n t s i d e a * 1 & C * 2 \end{matrix}$

The number of K atoms on product and reactant should be equal.

Implies, a=2c.

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Similar questions

The variable coefficients a, b, c and d are considered for balancing the chemical equation. Relationships between these variable are constructed by balancing the atoms of each element on either side of the reaction. Which of the following are correct?

(Note: coefficients should be natural numbers)

What will be the value of variable coefficients d, e, f, and g are considered for balancing the chemical equation.

We know that balancing of a chemical equation is entirely based on law of conservation of mass. However, the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction:

A B C_{3} \to A B + C_{2}

On applying POAC for A,B & C and relating the 3 equations, we get :

\frac{n_{A B C_{3}}}{2} = \frac{n_{A B}}{2} = \frac{n_{C_{2}}}{3}

n_{x}

: number of moles of X)
Thus, the coefficients of

A B C_{3}

A B

C_{2}

in the balanced chemical equation will be 2, 2 & 3 respectively and the balanced chemical equation can be represented as:

2 A B C_{3} \to 2 A B + 3 C_{2}

Now answer the following question.

Which of the following relation is correct regarding the numerical coefficients p, q, r in the balanced chemical equation,

p A + q B_{2} \to r A_{2} B_{5}

?

Q. An unbalanced chemical equation is shown below:

a H_{3} B O_{3} \to b B_{2} O_{3} + c H_{2} O

What are the coefficients(a,b,c) of a balanced equation?

Q. We know that balancing of a chemical equation is entirely based on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of conservation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction :

A B C_{3} \to A B + C_{2}

On applying POAC for A, B & C and relating the 3 equations, we get :

\frac{n_{A} B C_{3}}{2} = \frac{n_{A B}}{2} = \frac{n_{C_{2}}}{3}

n_{x} :

number of moles of X) Thus, the coefficients of

A B C_{3}, A B & C_{2}

in the balanced chemical equation will be 2, 2 & 3 respectively and the balanced chemical equation can be represented as :

2 A B C_{3} \to 2 A B + 3 C_{2}

Now answer the following question :

If the atomic masses of X and Y are 10 & 30 respectively, then the mass of

X Y_{3}

formed when 120 g

Y_{2}

reacts completely with sufficient amount of X is : Reaction

X + Y_{2} \to X Y_{3}

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