The variance of data 1001,1003,1006,1007,1009,1010 is
A
10
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B
15
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C
20
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D
50
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Solution
The correct option is A10 Variance remains unchanged on subtraction
i.e., variance of 1001,1003,1006,1007,1009,1010 will be same as that of 1,3,6,7,9,10 Variance=∑x2in−(¯¯¯x)2 ∴Variance=12+32+62+72+92+1026−(1+3+6+7+9+106)2 =2766−(366)2 =46−36=10