Question

The variance of the data 2, 4, 6, 8, 10 is:

• A. 6
• B. 7
• C. 8
• D. none of these

Answer 1

The correct option is C 8

$Mean\left(\overline{x}\right)=\frac{\sum x_i}{n}=(\frac{(2+4+6+8+10)}{5}=6$

$Variance\left({\sigma }^2\right)=\frac{\sum (x-\overline{x}{)}^2}{n}=\frac{(2-6{)}^2+(4-6{)}^2+(6-6{)}^2+(8-6{)}^2+(10-6{)}^2}{5}=\frac{(16+4+0+4+16)}{5}=\frac{40}{5}=8$