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B
(1+a22)n−(1+a2)2n
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C
(1+a2)2n−(1+a22)n
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D
none of these
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Solution
The correct option is B(1+a22)n−(1+a2)2n ¯X=∑fixi∑fi=nC0+a.nC1+a2.nC2+....an.nCnnC0+nC1+nC2+....nCn=(1+a)n2n . S.D.=
⎷∑fixi2∑fi−(∑fixi∑fi)2=
⎷nC0+a2.nC1+a4.nC2+....a2n.nCnnC0+nC1+nC2+....nCn−[(1+a)n2n]2√(1+a2)n2n−(1+a2)2n