The variation of displacement with time of a particle executing free simple harmonic motion is shown in the figure.
The potential energy \(U(x)\) versus time \((t)\) plot of the particle is correctly shown in figure : O &
A
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B
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C
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D
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Solution
The correct option is D We know that for SHM, potential energy is maximum at the extreme positions and is minimum at the mean position. Also, the sign of potential energy is the same throughout the SHM i.e. if we consider potential energy at mean position to be zero than potential energy is positive throughout the SHM. Hence, for the given displacement graph, the corresponding potential energy curve can be drawn as :