Question

The variation of PE of harmonic oscillator is as shown in figure. The spring constant is

• A. $1\times {10}^2{\text{Nm}}^{-1}$
• B. $1.5\times {10}^2{\text{Nm}}^{-1}$
• C. $2\times {10}^2{\text{Nm}}^{-1}$
• D. $3\times {10}^2{\text{Nm}}^{-1}$

Answer 1

The correct option is B $1.5\times {10}^2{\text{Nm}}^{-1}$

From the figure,
Amplitude of harmonic oscillator $\left(A\right)=(20-0)\text{mm}=20\text{mm}$
Potential energy of harmonivc oscillator
$\frac{1}{2}K{A}^2=(0.04-0.01)\text{J}$
$\Rightarrow \frac{1}{2}K{A}^2=0.03\text{J}$
$\Rightarrow K=\frac{0.06}{A^2}=\frac{0.08}{(0.02{)}^2}=150\text{N/m}$