The correct option is D 200 V/m
The relation between electric field (E) and electric potential (V) is given by
E=−dVdr
Here we can say that,
Electric field = Slope of the given graph between 0 to 2 cm
For 0 to 2 cm
dV=4 V−0 V=4 V
and
dr=(2−0) cm=2 cm
⇒dr=0.02 m
So,
E=−40.02=−200 V/m
The magnitude of electric field is 200 V/m
Hence, option (a) is correct.