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Question

The variation of potential with distance r from a fixed point is shown in Figure. The electric field at r=5cm, is?
1097468_a5e173bfd6034d2488aef9e6fe95c5e0.png

A
(2.5)V/cm
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B
(2.5)V/cm
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C
(2/5)cm
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D
(2/5)V/cm
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Solution

The correct option is A (2.5)V/cm
We know that, Electric field intensity, E=-dVdr , where V is the potential.
Here from the graph, it is clear that, at the distance r= 5 cm potential is 2.5V.
Electric field intensity, E= (05)V(64)cm=52
=2.5 V/cm


1109634_1097468_ans_47037bb0bbb64c58b60799d36be96a1a.png

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