wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The variation of pressure P with volume V for an ideal monoatomic gas during an adiabatic process is shown in figure. At point A, find the magnitude of the rate of change of pressure with volume.


A
3P05V0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5P03V0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3P02V0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5P02V0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 5P02V0
We can find the adiabatic coefficient γ by using,
γ=1+2f
Since the gas is monoatomic in nature,
Number of degrees of freedom (f)=3
Thus we get, γ=53

Equation of state of an adiabatic process in terms of P and V is given by
PVγ= constant
Differentiating both sides,
dPP=γdVV
We can write this as,
dPdV=γ×PV
At point A, from the data given in the figure, we can say that
dPdV=53×3P02V0=5P02V0
Thus, option (d) is the correct answer.

flag
Suggest Corrections
thumbs-up
35
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon