The correct option is C Air is assumed to follow ideal gas law.
The most basic expression of pressure variation in a static fluid in gravitation field is given by
dPdz=−ρg ....(1)
We assume air to follow ideal gas law
i.e PV=nRT
or P=mVRMT
⇒P=ρRMT ......(2)
For small variations in height, the density of a gas is assumed to be constant.
When we put expression (2) in (1), we get
dPdz=−PMRTg
Integrating on both sides,
⇒∫dPP=∫MgRTdz
If we further assume temperature to be constant,
⇒lnP=−MgRTz+C .......(3)
Let at z=0,P=P0
∴C=lnP0 ......(4)
Using equation (4) in equation (3), we get,
lnPP0=−MgzRT
or we can say that, P=P0e−MgzRT
For any elevation z=h,
P=P0e−MghRT
Thus, options (b) and (c) are the correct answers.