The variation of translational kinetic energy of one mole of a monoatomic gas with temperature is shown in the graph. Find tanθ.
A
3R2
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B
R
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C
9R2
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D
7R2
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Solution
The correct option is A3R2 Given:
Number of moles, n=1
Nature of gas is monoatomic
We know that,
Average translational kinetic energy of an ideal gas is given by, KE=nfRT2 ............(1)
where, n→ number of moles f→ no of degrees of freedom R→ universal gas constant T→ temperature
On comparing (1) with the equation of straight line , y=mx+c,
where y=KE & x=T Slope,m=tanθ=nfR2
and y-intercept,c=0
⇒tanθ=3R2
[ for monoatomic gas, f=3 and given n=1 ]