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Question

The variation of translational kinetic energy of one mole of a monoatomic gas with temperature is shown in the graph. Find tanθ.

A
3R2
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B
R
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C
9R2
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D
7R2
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Solution

The correct option is A 3R2
Given:
Number of moles, n=1
Nature of gas is monoatomic


We know that,
Average translational kinetic energy of an ideal gas is given by,
KE=nfRT2 ............(1)
where,
n number of moles
f no of degrees of freedom
R universal gas constant
T temperature

On comparing (1) with the equation of straight line , y=mx+c,
where y=KE & x=T
Slope, m=tanθ=nfR2
and y-intercept,c=0

tanθ=3R2
[ for monoatomic gas, f=3 and given n=1 ]

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