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Question

The variation of velocity of a particle moving along a straight line is shown in the figure. The magnitude of displacement of the particle in 4 s is :
292930_3070371cbed64adcba690a158a4f2f93.png

A
25 m
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B
30 m
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C
55 m
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D
60 m
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Solution

The correct option is B 55 m
Displacement from a velocity time graph is obtained as the area under the curve.
Between t = 0 s and 1 s:
A1=12×20×1=10 m
Between t= 1 s and 2 s:
A2=1×20=20 m
Between t = 2 s and 3 s:
A3=12×1×10+10×1=15 m
Between t = 3 s and 4 s:
A4=10×1=10 m
Hence total area under graph = 55m
Hence option C is correct.

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