Question

The $\overrightarrow{\upsilon }$ for the first emission line of hydrogen atomic spectrum in the Balmer series with respect to the Rydberg constant $R$ is:

Answer 1

For the first emission line in Balmer series, n1 = 2 and n2 = 3.

Using Rydberg's formula:

${\nu }^{-}=R(1/n_1^2-1/n_2^2)c{m}^{-1}$

$=R(1/2^2-1/3^2)c{m}^{-1}$

$=R(1/4-1/9)c{m}^{-1}=5R/36c{m}^{-1}$