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Question

The vector α^i+2^j+β^k lies in the plane of vectors b=^i+^j and c=^j+^k and bisects the angle between b and c Which one of the following gives possible values of α and β

A
α=2, β=2
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B
α=1, β=2
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C
α=2, β=1
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D
α=1, β=1
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Solution

The correct option is D α=1, β=1
b.(α^i+2^j+β^k)=|^b|(α2+4+β2)cosθ
(α+2)=(2)(α2+4+β2)cosθ------------(1)
a.(α^i)+α^j+β^k=|a|(22+4+β2)cosθ
(α+β)=(2)α2+4+β2cosθ--------------(2)
α+22+β=1
α=β------------(3)
2^i+2^j+β^k=μ(^i+^j)+λ(^j+^k) (collineorlity)
μ+λ=2
μ=αλ=β
α+β=2 --------------(4)
α=1β=1
54505_36329_ans.jpg

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