The vector ⎡⎢⎣12−1⎤⎥⎦ is an eigen vector of A=⎡⎢⎣−22−321−6−1−20⎤⎥⎦. The corresponding eigen value of A is _____.
A
1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
−1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C5 If λi be the eigen value of matrix A and Xi the corresponding eigen vector then. AXi=λiXi ⇒L.H.S=⎡⎢⎣−22−321−6−1−20⎤⎥⎦⎡⎢⎣12−1⎤⎥⎦=⎡⎢⎣510−5⎤⎥⎦=5⎡⎢⎣12−1⎤⎥⎦
= λiXi=RHS ⇒λi=5 is the eigen value of A corresponding to the eigen vector [12−1]T