The vector equation of the line passing through 3^i−5^j+7^k and perpendicular to the plane 3x−4y+5z=8 is
(where λ is a parameter)
A
3^i−5^j+7^k+λ(3^i+5^j−4^k)
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B
3^i−5^j+7^k+λ(2^i−^j+3^k)
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C
3^i−5^j+7^k+λ(3^i−4^j+5^k)
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D
3^i−5^j+7^k+λ(2^i+3^j+5^k)
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Solution
The correct option is C3^i−5^j+7^k+λ(3^i−4^j+5^k) Given plane is 3x−4y+5z=8 or (3^i−4^j+5^k)⋅(x^i+y^j+z^k)=8
This shows that →n=(3^i−4^j+5^k) is normal to the given plane. ∴ The required line is parallel to (3^i−4^j+5^k)
Since the required line passes through 3^i−5^j+7^k ∴ It's equation is given by 3^i−5^j+7^k+λ(3^i−4^j+5^k)
Where λ is a parameter.