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Question

The vector equation of the line passing through 3^i5^j+7^k and perpendicular to the plane 3x4y+5z=8 is
(where λ is a parameter)

A
3^i5^j+7^k+λ(3^i+5^j4^k)
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B
3^i5^j+7^k+λ(2^i^j+3^k)
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C
3^i5^j+7^k+λ(3^i4^j+5^k)
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D
3^i5^j+7^k+λ(2^i+3^j+5^k)
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Solution

The correct option is C 3^i5^j+7^k+λ(3^i4^j+5^k)
Given plane is 3x4y+5z=8 or (3^i4^j+5^k)(x^i+y^j+z^k)=8
This shows that n=(3^i4^j+5^k) is normal to the given plane.
The required line is parallel to (3^i4^j+5^k)
Since the required line passes through 3^i5^j+7^k
It's equation is given by
3^i5^j+7^k+λ(3^i4^j+5^k)
Where λ is a parameter.

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